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Forum: Electrical & Computer Engineering :: Digital Design :: Combinational Logic Design  | |||||||||
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| mohammadfawaz | Problem #50 | Wed 7 Oct 2009 4:01:00 PM | ||||||||||
Student Joined Sat 4 Apr 2009 Posts 642 |
Design the function below using a 4-input multiplexer with control
variables A and B and additional gates F = A’B’C’D’ +A’B’C’D +A’B’CD + A’BC’D + A’BCD’ + AB’C’D’ + AB’C’D
+ ABC’D’ + ABC’D Mohammad Fawaz |
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| mohammadfawaz | Wed 7 Oct 2009 4:02:00 PM | |||||||||||
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Student Joined Sat 4 Apr 2009 Posts 642 |
The best way solve this problem is to see what input we need to have for each possible value of AB - If AB = 00, then F = C’D’ + C’D + CD = C’ + CD = C’ + D - If AB = 01, then F = C’D + CD’ = CÅD - If AB = 10, then F = C’D’ + C’D = C’ - If AB = 11, then F = C’D’ + C’D = C’ These are inputs that we should have to the MUX: The circuit is shown below:   Mohammad Fawaz |
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