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Forum: Electrical & Computer Engineering :: Electric Circuits :: Sinusoidal steady state analysis  | |||||||||
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| aac13 | #20 | Fri 20 Mar 2009 6:30:00 PM | ||||||||||
Student Joined Wed 21 Jan 2009 Posts 151 |
use the mesh-current method to find the steady-state expression for v0  
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| aac13 | Fri 20 Mar 2009 6:31:00 PM | |||||||||||
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Student Joined Wed 21 Jan 2009 Posts 151 |
IÖ = Ia - Ib
-400/0° + ( 50 + j300 )Ia – 50Ib – 150( Ia – Ib ) = 0 (KVL) ( 150 – j100)Ib – 50Ia + 150( Ia – Ib) = 0 (KVL)
Solving, Ia = - 0.8 – j1.6 A Ib = -1.6 + j0.8 A V0 = 100Ib = -160 + j80 = 178.89/153.43° V v0 = 178.89 cos( 5000t + 153.43° ) V
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3/5
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