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Forum: Electrical & Computer Engineering :: Computer Organization :: MIPS  | |||||||||
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| nak31 | Problem #24 | Sun 4 Oct 2009 3:29:00 PM | ||||||||||
Student Joined Tues 31 Mar 2009 Posts 511 |
Problem 24:Translate the following switch statement in C++ into MIPS. Try to use as few registers as possible. Assume the following mapping: case 1: x = y + z; case 2: x = y - z; case -1: x = x - z; default: x = z + z;} |
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| nak31 | Sun 4 Oct 2009 3:29:00 PM | |||||||||||
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Student Joined Tues 31 Mar 2009 Posts 511 |
Solution:addi $t0, $0, 1 # case a="1<"/FONT> addi $t1, $0, 2 # case a="2<"/FONT> addi $t2, $0, -1 # case a="-1<"/FONT>
bne $s0, $t0, L2 # handle case 1 add $s1, $s2, $s3 j EXIT
L2: bne $s0, $t1, L3 # handle case 2 sub $s1, $s2, $s3 j EXIT
L3: bne $s0, $t2, D # handle case -1 sub $s1, $s1, $s3 j EXIT
D: add $s1, $s3, $s3 EXIT: |
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4/5
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