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Forum: Electrical & Computer Engineering :: Data Structures & Algorithms :: Disk Accessing  | |||||||||
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| nak31 | Problem #4 | Mon 20 Apr 2009 8:22:00 PM | ||||||||||
Student Joined Tues 31 Mar 2009 Posts 511 |
The time needed to read data found on 4
consecutive tracks is 215ms. Given the disk is rotating at 5400 rpm,
track-to-track seek time is 1.8ms, and the interleaving factor is 4. Find the disk
access seek time.
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| nak31 | Mon 20 Apr 2009 8:23:00 PM | |||||||||||
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Student Joined Tues 31 Mar 2009 Posts 511 |
Solution 4:
Rotational Delay is 0.5 * (1/frequency) = 0.5 * (60/5400) First track= Seek time + Rotational delay + interleaving
factor x time to read one track Remaining track = Track-to-track seek time + Rot. delay + int. factor x time to read one
track Total time = time to read first
track + 7* time to read remaining track Seek time = 215 – 205.2 ms
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4/5
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