At node a:
(V – 6IX – 20) / 4 + V/6 + V/9 = 0V/4 - 6IX / 4 - 5 + V/6 + V/9 = 0IX = V/6
Solving, V = 18 Volts
Ohm’s law: I = V / R = -18 / 9 = -2 A